16( k^4+k’^2 ) | 温故知新

温故知新

毎日更新が目標です・・・

τ

= √-t ( t > 0 ) :

16( k^4+k’^2 )

=

12 ( t = 1 )

80( √2-1 )^2 ( t = 2 )

15 ( t = 3 )

255/16 ( t = 7 )