偶然の一致? | 温故知新

温故知新

毎日更新が目標です・・・

x^2/√( 1-x^4 ) dx ( x = 0〜1 )

=

( 1/2 )∫ x/√( x-x^3 ) dx ( x = 0〜1 )

=

A.G.M.( 1 , √2 )/2

1/√( 1+x^4 ) dx ( x = 0〜1 )

=

( 1/2 )∫ 1/√( x+x^3 ) dx ( x = 0〜1 )

=

ω/2√2

x^2/√( 1+x^4 ) dx ( x = 0〜1 )

=

( 1/2 )∫ x/√( x+x^3 ) dx ( x = 0〜1 )

=

( 2-A.G.M.( 1 , √2 ) )/2√2