AI comparison : case of Z80 assembly language | AI-created blog with Ainan Kuma Farm

AI-created blog with Ainan Kuma Farm

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prompt :

Create Z80 Assembly code to add 3 ten times

(Actually, prompted in Japanese and translated the response in English)


Response by ChatGPT 3.5

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Sure, here's the program in Z80 assembly language that adds 3 to itself 10 times:

.org 0000h

start:
    LD  A, 0         ; Initialize register A to 0
    LD  B, 10        ; Load 10 into register B
    
loop:
    ADD A, 3         ; Add 3 to register A
    DJNZ loop        ; Decrement B; if not zero, jump back to loop
    
    ; Add any necessary program termination here (optional)
    
    HALT             ; End the program
    
.end


This program adds 3 to itself 10 times and stores the result in register A.

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Response by Google Gemini

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Code snippet

; Initialize variables
LD A, 03 ; Load value 3 into register A
LD HL, 0000 ; Load value 0000 into HL register (counter)

; Start the loop
loop:
    ADD A, A ; Add A to itself (increment A by 1)
    DCR HL ; Decrement HL register (count down)
    JNZ loop ; Jump to 'loop' if HL is not zero (counter > 0)

; End of loop
HALT ; Halt execution

; Output the result
LD B, A ; Load value from A to register B
OUT (0x01), B ; Output value from B to port 0x01 (display on screen)


Explanation:

    Initialize variables:
        LD A, 03: Loads the value 3 into register A.
        LD HL, 0000: Loads the value 0000 into the HL register, which will be used as a counter.

    Start the loop:
        loop:: This label marks the beginning of the loop.

    Increment the sum:
        ADD A, A: Adds the value in register A to itself, effectively incrementing A by 1.

    Decrement the counter:
        DCR HL: Decrements the value in the HL register by 1.

    Check if the loop continues:
        JNZ loop: Jumps back to the loop label if the value in HL is not zero (counter > 0). This means the loop will continue until the counter reaches zero.

    End of the loop:
        HALT: Halts the execution of the program.

    Output the result:
        LD B, A: Loads the value from register A into register B.
        OUT (0x01), B: Outputs the value from register B to port 0x01, which is typically connected to a display device. This will display the final sum on the screen.

This code effectively adds the value 3 to itself ten times, storing the result in register A and displaying it on the screen.

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Response by Microsoft Copilot

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Of course. Below is a program using Z80 assembly language that adds 3 ten times. This program uses the B register as a counter and stores the result in the HL register pair.

Assembly

    LD B, 10      ; Load 10 into the B register (used as a counter)
    LD HL, 0      ; Initialize the HL register pair to 0
AddLoop:
    ADD HL, DE    ; Add the value in the DE register pair (3) to HL
    DJNZ AddLoop  ; Decrement the value in the B register, if not zero, loop back to AddLoop
    RET           ; End of the program


Before running this program, you need to load 3 into the DE register pair. For example, you can do this with LD DE, 3. After the program finishes, the HL register pair will contain the result of adding 3 ten times. Please give it a try! 👩‍💻"

I hope this helps clarify the program for you! If you have any more questions or need further assistance, feel free to ask. 😊

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Picture of Z80 CPU created with Microsoft Designer

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Note:

Code by Google Gemini contains error. HL register should load 10 (or &h000A).

The main CPU of the picture is not Z80, but the Chip upper-right of the main CPU looks like Z80.

 

日本語版はこちら

https://blog.kuma-farm-japan.jp/