J(τ= √-7 ) | 温故知新

温故知新

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楕円曲線 C : y^2 = 4x^3-595x-2793

( e1 , e2 , e3 )

= ( 7/2+4√7 , -7 , 7/2-4√7 )

k(τ)

= sinθ

= √( 8-3√7 )/4

k’(τ)

= cosθ

= √( 8+3√7 )/4

τ

= √-7

q

= exp( -√7π)

a

= ( 2sin2θ)^2

= 1/2^4

J(τ= √-7 )

= 2^4( 2^4-a )^3/a^2

= 16581375

= 255^3

J( ( 1+√-7 )/2 )

= 2^8( 1-a )^3/a

= 3375

= 15^3

 

q.e.d.